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JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
The ratio \(\frac{{{K_p}}}{{{K_c}}}\) for the reaction \(CO\left( g \right) + \frac{1}{2}{O_2}\left( g \right) \rightleftharpoons C{O_2}\left( g \right)\) is
- A \(\frac{1}{{\sqrt {RT} }}\)
- B \({\left( {RT} \right)^{1/2}}\)
- C \({RT}\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{{\sqrt {RT} }}\)
Step-by-step Solution
Detailed explanation
\({K_P} = {K_C}{(RT)^{\Delta {n_g}}}\) For the reaction \(CO(g) + \frac{1}{2}{O_2}(g) \leftrightarrow C{O_2}(g)\) \(\Delta {n_g} = 1 - \left( {1 + \frac{1}{2}} \right) = - \frac{1}{2}\)…
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