JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
Consider the following complex ions \( \mathrm{P}=\left[\mathrm{FeF}_6\right]^{3-} \) , \( \mathrm{Q}=\left[\mathrm{V}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} \) , \( \mathrm{R}=\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}\) The correct order of the complex ions, according to their spin only magnetic moment values (in \(B.M.\)) is :
- A \(R < Q < P\)
- B \(R < P < Q\)
- C \(Q < R < P\)
- D \(Q < P < R\)
Answer & Solution
Correct Answer
(C) \(Q < R < P\)
Step-by-step Solution
Detailed explanation
\(\left[\mathrm{FeF}_6\right]^{3-}: \mathrm{Fe}^{+3}:[\mathrm{Ar}] 3 \mathrm{~d}^5\) F : Weak field Ligand No. of unpaired electron'\(s=5\) \( \mu=\sqrt{5(5+2)} \) \( \mu=\sqrt{35} \mathrm{BM} \)…
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