JEE Mains · Chemistry · STD 11 - 2. structure of atom
A metal surface is exposed to \(500\, \mathrm{~nm}\) radiation. The threshold frequency of the metal for photoelectric current is \(4.3 \times 10^{14}\, \mathrm{~Hz}\). The velocity of ejected electron is \(.......\,\times 10^{5} \mathrm{~ms}^{-1}\) (Nearest integer) [Use : \(\left.\mathrm{h}=6.63 \times 10^{-34}\, \mathrm{Js}, \mathrm{m}_{\mathrm{e}}=9.0 \times 10^{-31}\, \mathrm{~kg}\right]\)
- A \(7\)
- B \(5\)
- C \(1\)
- D \(500\)
Answer & Solution
Correct Answer
(B) \(5\)
Step-by-step Solution
Detailed explanation
\(v:\) speed of electron having max. K.E. \(\Rightarrow\) from Einstein equation : \(\mathrm{E}=\phi+\mathrm{K} \cdot \mathrm{E}_{\cdot \max }\) \(\Rightarrow \frac{\mathrm{hc}}{\lambda}=\mathrm{h} v_{0}+\frac{1}{2} \mathrm{mv}^{2}\)…
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