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JEE Advanced · Physics · 9. Gravitation

Two bodies, each of mass M, are kept fixed with a separation of 2L. A particle of mass m is projected from the midpoint of the line joining their centers, perpendicular to the line. The gravitational constant is G. The correct statement (s) is (are) :

  1. A The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is 4GML.
  2. B The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is 2GML.
  3. C The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is 2GML.
  4. D The energy of the mass m remains constant.
Verified Solution

Answer & Solution

Correct Answer

(D) The energy of the mass m remains constant.

Step-by-step Solution

Detailed explanation

Applying mechanical energy conservation, Ui+KEi=Uf+KEf
-GMmL×2+12mv2=0+0
v=4GML

v= 2GML
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