JEE Advanced · Physics · 12. Thermal Properties
Match the temperature of a black body given in List- with an appropriate statement in List-, and choose the correct option.
[Given: Wien’s constant as and ]
| List- | List- | ||
| The radiation at peak wavelength can lead to emission of photoelectrons from a metal of work function | |||
| The radiation at peak wavelength is visible to human eye | |||
| The radiation at peak emission wavelength will result in the widest central maximum of a single slit diffraction | |||
| The power emitted per unit area is of that emitted by a blackbody at temperature | |||
| The radiation at peak emission wavelength can be used to image human bones |
- A
- B
- C
- D
Answer & Solution
Correct Answer
(C)
Step-by-step Solution
Detailed explanation
Maximum wavelength for each case:
Now for List-:
| (P) 2000 K | \(\begin{array}{l}\lambda_m T=b \\ \Rightarrow \lambda_m=\frac{b}{T}=\frac{2.9 \times 10^{-3}}{2000} \\ =1.45 \times 10^{-6} m \\ =1450 nm\end{array}\) |
| (Q) 3000 K | \(\begin{array}{l}\lambda_m T=b \\ \Rightarrow \lambda_m=\frac{2.9 \times 10^{-3}}{3000} \\ =966.66 nm\end{array}\) |
| (R) 5000 K | \(\begin{array}{l}\lambda_m T=b \\ \Rightarrow \lambda_m=\frac{2.9 \times 10^{-3}}{5000} \\ =580 nm\end{array}\) |
| (S) 10000 K | \(\begin{array}{l}\lambda_m T=b \\ \Rightarrow \lambda_m=\frac{2.9 \times 10^{-3}}{10,000} \\ =290 nm\end{array}\) |
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