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JEE Advanced · Physics · 19. Current Electricity

Incandescent bulbs are designed by keeping in mind that the resistance of their filament increases with the increase in temperature. If at room temperature, \(100 \mathrm{~W}, 60 \mathrm{~W}\) and \(40 \mathrm{~W}\) bulbs have filament resistances \(R_{100}, R_{60}\) and \(R_{40}\), respectively, the relation between these resistances is

  1. A \(\frac{1}{R_{100}}=\frac{1}{R_{40}}+\frac{1}{R_{60}}\)
  2. B \(R_{100}=R_{40}+R_{60}\)
  3. C \(R_{100}>R_{60}>R_{40}\)
  4. D \(\frac{1}{R_{100}}>\frac{1}{R_{60}}>\frac{1}{R_{40}}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{1}{R_{100}}>\frac{1}{R_{60}}>\frac{1}{R_{40}}\)

Step-by-step Solution

Detailed explanation

\(R=\frac{V^2}{P}\) or \(R \propto \frac{1}{P}\) \(\therefore \quad \frac{1}{R_{100}}>\frac{1}{R_{60}}>\frac{1}{R_{40}}\)
Hence, the correct option is (d).
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