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JEE Advanced · Physics · 26. Dual Nature

In a historical experiment to determine Planck's constant, a metal surface was irradiated with light of different wavelengths. The emitted photoelectron energies were measured by applying a stopping potential. The relevant data for the wavelength \((\lambda)\) of incident light and the corresponding stopping potential (\(V_0\)) are given below:
\(\lambda(\mu m)\)Volt
0.32.0
0.41.0
0.50.4
Given that \(c=3 \times 10^8 m s^{-1}\) and \(e=1.6 \times 10^{-19} C\), Planck's constant (in units of J s) found from such an experiment is :

  1. A 6.0×10-34
  2. B 6.4×10-34
  3. C 6.6×10-34
  4. D 6.8×10-34
Verified Solution

Answer & Solution

Correct Answer

(B) 6.4×10-34

Step-by-step Solution

Detailed explanation

KEmax=hCλ-ϕ eV0=hCλ-ϕ
1.6×10-19×2=h×3×1083000×10-10-ϕ .....(i)
1.6×10-19×1=h×3×1084000×10-10-ϕ .......(ii)
From (ii) ϕ=h×3×1084000×10-10-1.6×10-19
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