JEE Advanced · Physics · 15. Oscillations
Function \(x=A \sin ^2 \omega t+B \cos ^2 \omega t+C\) \(\sin \omega t \cos \omega t\) represents SHM.
- A For any value of \(A, B\) and \(C\) (except \(C=0\) )
- B If \(A=-B, C=2 B\), amplitude \(=|B \sqrt{2}|\)
- C If \(A=B ; C=0\)
- D If \(A=B ; C=2 B\), amplitude \(=|B|\)
Answer & Solution
Correct Answer
(D) If \(A=B ; C=2 B\), amplitude \(=|B|\)
Step-by-step Solution
Detailed explanation
For \(A=-B\) and \(C=2 B\)
\(
X=B \cos 2 \omega t+B \sin 2 \omega t=\)\(\sqrt{2 B} \sin \left(2 \omega t+\frac{\pi}{4}\right)
\)
This is equation of SHM of amplitude \(\sqrt{2} B\)
If \(A=B\) and \(C=2 B\), then \(X=B+B \sin 2 \omega t\)
This is also equation of SHM about the point \(X=B\). Function oscillates between \(X=0\) and \(X=2 B\) with amplitude \(B\).
\(
X=B \cos 2 \omega t+B \sin 2 \omega t=\)\(\sqrt{2 B} \sin \left(2 \omega t+\frac{\pi}{4}\right)
\)
This is equation of SHM of amplitude \(\sqrt{2} B\)
If \(A=B\) and \(C=2 B\), then \(X=B+B \sin 2 \omega t\)
This is also equation of SHM about the point \(X=B\). Function oscillates between \(X=0\) and \(X=2 B\) with amplitude \(B\).
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