JEE Advanced · Physics · 19. Current Electricity
Figure shows three resistor configurations \(R_1, R_2\) and \(R_3\) connected to \(3 \mathrm{~V}\) battery. If the power dissipated by the configuration \(R_1, R_2\) and \(R_3\) is \(P_1, P_2\) and \(P_3\), respectively, then
- A \(P_1>P_2>P_3\)
- B \(P_1>P_3>P_2\)
- C \(P_2>P_1>P_3\)
- D \(P_3>P_2>P_1\)
Answer & Solution
Correct Answer
(C) \(P_2>P_1>P_3\)
Step-by-step Solution
Detailed explanation
Applying \(P=\frac{V^2}{R}\)
\(R_1=1 \Omega, R_2=0.5 \Omega\) and \(R_3=2 \Omega, V_1=V_2=V_3=3\) volt
\(\therefore \quad P_1=\frac{(3)^2}{1}=9 \mathrm{~W}\)
\(\quad P_2=\frac{(3)^2}{0.5}=18 \mathrm{~W}\) and \(P_3=\frac{(3)^2}{2}=4.5 \mathrm{~W}\)
\(\therefore \quad P_2>P_1>P_3\)
\(\therefore \quad\) correct option is (c).
\(R_1=1 \Omega, R_2=0.5 \Omega\) and \(R_3=2 \Omega, V_1=V_2=V_3=3\) volt
\(\therefore \quad P_1=\frac{(3)^2}{1}=9 \mathrm{~W}\)
\(\quad P_2=\frac{(3)^2}{0.5}=18 \mathrm{~W}\) and \(P_3=\frac{(3)^2}{2}=4.5 \mathrm{~W}\)
\(\therefore \quad P_2>P_1>P_3\)
\(\therefore \quad\) correct option is (c).
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