ExamBro
ExamBro
JEE Advanced · Physics · 13. Thermodynamics

Answer the following by appropriately matching the lists based on the information given in the paragraph.
In a thermodynamics process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by TΔX, where T is temperature of the system and ΔX is the infinitesimal change in a thermodynamic quantity X of the system. For a mole of monatomic ideal gas X=32R lnTTA+R lnVVA. Here, R is gas constant, V is volume of gas, TA and VA are constants.
The List-I below gives some quantities involved in a process and List-II gives some possible values of these quantities.
Column - I Column - II
(a)Work done by the system in process 123(p)13RT0 ln2
(b)Change in internal energy in process 123(q)13RT0
(c)Heat absorbed by the system in process 123(r)RT0
(d)Heat absorbed by the system in process 12(s)43RT0
(t)13RT03+ln 2
(u)56RT0

If the process on one mole of monatomic ideal gas is as shown in the PV -diagram with P0V0=13RT0, the correct match is

  1. A a-s, b-r, c-q, d-t
  2. B a-q, b-r, c-p, d-u
  3. C a-q, b-s, c-r, d-u
  4. D a-q, b-r, c-s, d-u
Verified Solution

Answer & Solution

Correct Answer

(D) a-q, b-r, c-s, d-u

Step-by-step Solution

Detailed explanation

a W123=W12+W23
=P02V0-V0+0=P0V0
W123=P0V0
=RT03aq
Process 12isobaricand 23isochoric
b U123=323P02×2V0-P0V0
=32×2P0V0=3P0V0=RT0br
Same subject
Explore more questions on app
From JEE Advanced
Explore more questions on app