JEE Advanced · Physics · 26. Dual Nature
An \(\alpha\)-particle and a proton are accelerated from rest by a potential difference of \(100 \mathrm{~V}\). After this, their de Broglie wavelengths are \(\lambda_\alpha\) and \(\lambda_p\) respectively. The ratio \(\frac{\lambda_p}{\lambda_\alpha}\), to the nearest integer, is
- A 2
- B 3
- C 5
- D 4
Answer & Solution
Correct Answer
(B) 3
Step-by-step Solution
Detailed explanation
\(\lambda =\frac{h}{P}=\frac{h}{\sqrt{2 q q V m}} \text { or } \lambda \propto \frac{1}{\sqrt{q m}} \)
\( \frac{\lambda_p}{\lambda_\alpha} =\sqrt{\frac{q_\alpha}{q_p} \cdot \frac{m_{\propto}}{m_p}}=\sqrt{\frac{(2)(4)}{(1)(1)}}=2.828\)
The nearest integer is 3 .
\(\therefore\) answer is 3 .
\( \frac{\lambda_p}{\lambda_\alpha} =\sqrt{\frac{q_\alpha}{q_p} \cdot \frac{m_{\propto}}{m_p}}=\sqrt{\frac{(2)(4)}{(1)(1)}}=2.828\)
The nearest integer is 3 .
\(\therefore\) answer is 3 .
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