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JEE Advanced · Physics · 13. Thermodynamics

An ideal gas is undergoing a cyclic thermodynamic process in different ways as shown in the corresponding P-V diagrams in column 3 of the table. Consider only the path from state 1 to state 2. W denotes the corresponding work done on the system. The equations and plots in the table have standard notations as used in thermodynamic process. Here γ is the ratio of heat capacities at constant pressure and constant volume. The number of moles in the gas is n.
Column – 1Column – 2Column – 3
(I) \(W_{1 \rightarrow 2}=\frac{1}{\gamma-1}\) \(\left(P_2 V_2-P_1 V_1\right)\)(i) Isothermal(P)
(II) \(W_{1 \rightarrow 2}=\) \(-P V_2+P V_1\)(ii) Isochoric(Q)
(III) \(W_{1 \rightarrow 2}=0\)(iii) Isobaric(R)
(IV) \(W_{1 \rightarrow 2}=\) \(-n R T \ln \left(\frac{V_2}{V_1}\right)\)(iv) Adiabatic(S)
Which one of the following options is the correct combination?

  1. A (IV(ii(S)
  2. B (III(ii(S)
  3. C (I(ii(Q)
  4. D (III(iv(R)
Verified Solution

Answer & Solution

Correct Answer

(B) (III(ii(S)

Step-by-step Solution

Detailed explanation

The correct match is (III) (ii) (S)
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