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JEE Advanced · Physics · 17. Electrostatics

A uniformly charged thin spherical shell of radius \(R\) carries uniform surface charge density of \(\sigma\) per unit area. It is made of two hemispherical shells, held together by pressing them with force \(F\) (see figure). \(F\) is proportional to

  1. A \(\frac{1}{\varepsilon_0} \sigma^2 R^2\)
  2. B \(\frac{1}{\varepsilon_0} \sigma^2 R\)
  3. C \(\frac{1}{\varepsilon_0} \frac{\sigma^2}{R}\)
  4. D \(\frac{1}{\varepsilon_0} \frac{\sigma^2}{R^2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{\varepsilon_0} \sigma^2 R^2\)

Step-by-step Solution

Detailed explanation

Electrical force per unit area \(=\frac{1}{2} \varepsilon_0 E^2\)
\(
=\frac{1}{2} \varepsilon_0\left(\frac{\sigma}{\varepsilon_0}\right)^2=\frac{\sigma^2}{2 \varepsilon_0}
\)
Projected area \(=\pi R^2\)
\(\therefore\) net electrical force \(=\left(\frac{\sigma^2}{2 \varepsilon_0}\right)\left(\pi R^2\right)\)
In equilibrium, this force should be equal to the applied force.
\(\therefore \quad F=\frac{\pi \sigma^2 R^2}{2 \varepsilon_0}\)
or \(\quad F \propto \frac{\sigma^2 R^2}{\varepsilon_0}\)
\(\therefore\) The correct option is (a).
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