JEE Advanced · Physics · 16. Waves & Sound
A transverse sinusoidal wave moves along a string in the positive \(x\)-direction at a speed of \(10 \mathrm{~cm} / \mathrm{s}\). The wavelength of the wave is \(0.5 \mathrm{~m}\) and its amplitude is \(10 \mathrm{~cm}\). At a particular time \(t\), the snap-shot of the wave is shown in figure. The velocity of point \(P\) when its displacement is \(5 \mathrm{~cm}\) is

- A \(\frac{\sqrt{3} \pi}{50} \hat{\mathbf{j}} \mathrm{m} / \mathrm{s}\)
- B \(-\frac{\sqrt{3} \pi}{50} \hat{j} \mathrm{~m} / \mathrm{s}\)
- C \(\frac{\sqrt{3} \pi}{50} \hat{\mathbf{i}} \mathrm{m} / \mathrm{s}\)
- D \(-\frac{\sqrt{3} \pi}{50} \hat{\mathbf{i}} \mathrm{m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(\frac{\sqrt{3} \pi}{50} \hat{\mathbf{j}} \mathrm{m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
Particle velocity \(v_p=-v\) (slope of \(y-x\) graph)
Here,\(v=+v e\), as the wave is travelling in positive \(x\)-direction.
Slope at \(P\) is negative.
\(\therefore\) Velocity of particle is in positive \(y(+\overrightarrow{\mathbf{j}})\) direction.
\(\therefore\) correct option is (a).
Here,\(v=+v e\), as the wave is travelling in positive \(x\)-direction.
Slope at \(P\) is negative.
\(\therefore\) Velocity of particle is in positive \(y(+\overrightarrow{\mathbf{j}})\) direction.
\(\therefore\) correct option is (a).
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