JEE Advanced · Physics · 8. Rotational Motion
A sphere is rolling without slipping on a fixed horizontal plane surface. In the figure, \(A\) is the point of contact. \(B\) is the centre of the sphere and \(C\) is its topmost point. Then,

- A \(\overrightarrow{\mathbf{v}}_C-\overrightarrow{\mathbf{v}}_A=2\left(\overrightarrow{\mathbf{v}}_B-\overrightarrow{\mathbf{v}}_C\right)\)
- B \(\overrightarrow{\mathbf{v}}_C-\overrightarrow{\mathbf{v}}_B=\overrightarrow{\mathbf{v}}_B-\overrightarrow{\mathbf{v}}_A\)
- C \(\left|\overrightarrow{\mathbf{v}}_C-\overrightarrow{\mathbf{v}}_A\right|=2\left|\overrightarrow{\mathbf{v}}_B-\overrightarrow{\mathbf{v}}_C\right|\)
- D \(\left|\overrightarrow{\mathbf{v}}_C-\overrightarrow{\mathbf{v}}_A\right|=4\left|\overrightarrow{\mathbf{v}}_B\right|\)
Answer & Solution
Correct Answer
(C) \(\left|\overrightarrow{\mathbf{v}}_C-\overrightarrow{\mathbf{v}}_A\right|=2\left|\overrightarrow{\mathbf{v}}_B-\overrightarrow{\mathbf{v}}_C\right|\)
Step-by-step Solution
Detailed explanation
\(v_A=0, v_B=v \text { and } v_C=2 v\)


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