JEE Advanced · Physics · 16. Waves & Sound
A horizontal stretched string, fixed at two ends, is vibrating in its fifth harmonic according to the equation, \(y ( x , t )=(0.01 m) \sin \left[\left(62.8 m^{-1}\right) x \right]\) \(\cos \left[\left(628 s^{-1}\right) t \right]\). Assuming \(\pi=3.14\), the correct statement(s) is (are)
- A The number of nodes is 5.
- B The length of the string is 0.25 m.
- C The maximum displacement of the midpoint of the string, from its equilibrium position is 0.01 m.
- D The fundamental frequency is 100 Hz.
Answer & Solution
Correct Answer
(C) The maximum displacement of the midpoint of the string, from its equilibrium position is 0.01 m.
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