JEE Advanced · Mathematics · 26. Indefinite Integration
The value of \(\int \frac{\left(x^2-1\right) d x}{x^3 \sqrt{2 x^4-2 x^2+1}}\) is
- A
\(2 \sqrt{2-\frac{2}{x^2}+\frac{1}{x^4}}+C\)
- B
\(2 \sqrt{2+\frac{2}{x^2}+\frac{1}{x^4}}+C\)
- C
\(\frac{1}{2} \sqrt{2-\frac{2}{x^2}+\frac{1}{x^4}}+C\)
- D
None of these
Answer & Solution
Correct Answer
(C)
\(\frac{1}{2} \sqrt{2-\frac{2}{x^2}+\frac{1}{x^4}}+C\)
Step-by-step Solution
Detailed explanation
Let \(\quad I=\int \frac{\left(x^2-1\right) d x}{x^3 \sqrt{2 x^4-2 x^2+1}}\),
On dividing numerater and denominator by \(x^5\), we get
\[
=\int \frac{\left(\frac{1}{x^3}-\frac{1}{x^5}\right) d x}{\sqrt{2-\frac{2}{x^2}+\frac{1}{x^4}}}
\]
put \(2-\frac{2}{x^2}+\frac{1}{x^4}=t \Rightarrow\left(\frac{4}{x^3}-\frac{4}{x^5}\right) d x=d t\)
\[
\therefore \quad I=\frac{1}{4} \int \frac{d t}{\sqrt{t}}=\frac{1}{4} \cdot \frac{t^{1 / 2}}{1 / 2}=\frac{1}{2} \sqrt{t}+c=\frac{1}{2} \sqrt{2-\frac{2}{x^2}+\frac{1}{x^4}}+C
\]
On dividing numerater and denominator by \(x^5\), we get
\[
=\int \frac{\left(\frac{1}{x^3}-\frac{1}{x^5}\right) d x}{\sqrt{2-\frac{2}{x^2}+\frac{1}{x^4}}}
\]
put \(2-\frac{2}{x^2}+\frac{1}{x^4}=t \Rightarrow\left(\frac{4}{x^3}-\frac{4}{x^5}\right) d x=d t\)
\[
\therefore \quad I=\frac{1}{4} \int \frac{d t}{\sqrt{t}}=\frac{1}{4} \cdot \frac{t^{1 / 2}}{1 / 2}=\frac{1}{2} \sqrt{t}+c=\frac{1}{2} \sqrt{2-\frac{2}{x^2}+\frac{1}{x^4}}+C
\]
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Mathematics
- In a study about a pandemic, data of persons was collected. It was found that persons had symptom of fever, persons had symptom of cough, persons had symptom of breathing problem, persons had symptom of fever or cough or both, persons had symptom of cough or breathing problem or both, persons had symptom of fever or breathing problem or both, persons had all three symptoms (fever, cough and breathing problem). If a person is chosen randomly from these persons, then the probability that the person has at most one symptom is ______.JEE Advanced 2022 Easy
- Let . Then Sn can take value(s)JEE Advanced 2013 Hard
- Let \(a_{1}, a_{2}, a_{3}, \ldots . .\) be in harmonic progression with \(a_{1}=5\) and \(a_{20}=25\). The least positive integer \(n\) for which \(a_{n} < 0\) isJEE Advanced 2012 Medium
- Statement I The curve \(y=-\frac{x^2}{2}+x+1\) is symmetric with respect to the line \(x=1\)
Statement II A parabola is symmetric about its axis.JEE Advanced 2007 Easy - Let be positive valued angles (in radian) such that . Define the complex numbers for , where . Consider the statements and given below:
\(P:\left|z_2-z_1\right|+\left|z_3-z_2\right|+\cdots+\left|z_{10}-z_9\right|\) \(+\left|z_1-z_{10}\right| \leq 2 \pi \)
\( Q:\left|z_2^2-z_1^2\right|+\left|z_3^2-z_2^2\right|+\cdots+\left|z_{10}^2-z_9^2\right|\) \(+\left|z_1^2-z_{10}^2\right| \leq 4 \pi\)JEE Advanced 2021 Medium - If the function is defined by , then which of the following statements is TRUE?JEE Advanced 2020 Easy
More PYQs from JEE Advanced
- The sides of a right-angled triangle are in arithmetic progression. If the triangle has area 24 square units, then what is the length of its smallest side?JEE Advanced 2017 Medium
- Considering only the principal values of the inverse trigonometric functions, the value of is _______. (If the numerical value has more than two decimal places, truncate/round-off the value to TWO decimal places)JEE Advanced 2022 Easy
- The substituents \(R_{1}\) and \(R_{2}\) for nine peptides are listed in the table given below. How many of these peptides are positively charged at \(\mathrm{pH}=7.0\) ?

\(\begin{array}{|c|c|c|}\hline Peptide & \mathbf{R}_{\mathbf{1}} & \mathbf{R}_{\mathbf{2}} \\\hline I & \mathrm{H} & \mathrm{H} \\\hline II & \mathrm{H} & \mathrm{CH}_{3} \\\hline III & \mathrm{CH}_{2} \mathrm{COOH} & \mathrm{H} \\\hline IV & \mathrm{CH}_{2} \mathrm{CONH}_{2} & \left(\mathrm{CH}_{2}\right)_{4} \mathrm{NH}_{2} \\\hline V & \mathrm{CH}_{2} \mathrm{CONH}_{2} & \mathrm{CH}_{2} \mathrm{CONH}_{2} \\\hline VI & \left(\mathrm{CH}_{2}\right)_{4} \mathrm{NH}_{2} & \left(\mathrm{CH}_{2}\right)_{4} \mathrm{NH}_{2} \\\hline VII & \mathrm{CH}_{2} \mathrm{COOH} & \mathrm{CH}_{2} \mathrm{CONH}_{2} \\\hline VIII & \mathrm{CH}_{2} \mathrm{OH} & \left(\mathrm{CH}_{2}\right)_{4} \mathrm{NH}_{2} \\\hline IX & \left(\mathrm{CH}_{2}\right)_{4} \mathrm{NH}_{2} & \mathrm{CH}_{3} \\\hline\end{array}\)JEE Advanced 2012 Hard - A solution when diluted with \(\mathrm{H}_2 \mathrm{O}\) and boiled, it gives a white precipitate. On addition of excess \(\mathrm{NH}_4 \mathrm{Cl} / \mathrm{NH}_4 \mathrm{OH}\), the volume of precipitate decreases leaving behind a white gelatinous precipitate. Identify the precipitate which dissolves in \(\mathrm{NH}_4 \mathrm{OH} / \mathrm{NH}_4 \mathrm{Cl}\).JEE Advanced 2006 Hard
- Paragraph:
Read the following passage and answer the questions.
Let \(A B C D\) be a square of side length 2 units. \(C_2\) is the circle through vertices \(A, B, C, D\) and \(C_1\) is the circle touching all the sides of square \(A B C D\). \(L\) is the line through \(A\).Question:
A line \(M\) through \(A\) is drawn parallel to \(B D\). Points \(S\) moves such that its distances from the line \(B D\) are the vertex \(A\) are equal. If locus of \(S\) cuts \(M\) at \(T_2\) and \(T_3\) and \(A C\) at \(T_1\), then area of \(\Delta T_1 T_2 T_3\) isJEE Advanced 2006 Medium - For the cell , when the concentration of is times the concentration of , the expression for is
Faraday's constant, universal gas constant, temperature,JEE Advanced 2017 Easy