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JEE Advanced · Mathematics · 5. Sequences & Series

The sides of a right-angled triangle are in arithmetic progression. If the triangle has area 24 square units, then what is the length of its smallest side?

  1. A 3
  2. B 6
  3. C 9
  4. D 12
Verified Solution

Answer & Solution

Correct Answer

(B) 6

Step-by-step Solution

Detailed explanation

Let three sides of triangle be: a-d, a, a+d.

Where, d>0, a>0.
length of smallest side =a-d units
Now, ( a+d ) 2 = a 2 + ( ad ) 2
aa-4d=0
a=4d .....(i)
(As a = 0 is rejected)
Also, 12a.a-d=24
aa-d=48 .....(ii)
From (i) and (ii), we get a=8, d=2
Hence, length of smallest side is
a-d=8-2=6units
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