JEE Advanced · Mathematics · 13. Parabola
Consider the parabola \(y^2=8 x\). Let \(\Delta_1\) be the area of the triangle formed by the end points of its latusrectum and the point \(P\left(\frac{1}{2}, 2\right)\) on the parabola and \(\Delta_2\) be the area of the triangle formed by drawing tangents at \(P\) and at the end points of the latusrectum. Then, \(\frac{\Delta_1}{\Delta_2}\) is
- A 2
- B 4
- C 6
- D 8
Answer & Solution
Correct Answer
(A) 2
Step-by-step Solution
Detailed explanation
As, we know area of triangle formed by three points on parabola is twice the area of triangle formed by corresponding tangents, i.e. area of \(\triangle P Q R=2\) area of \(\Delta T_1 T_2 T_3\).

\(\therefore \quad \Delta_1=2 \Delta_2\) or \(\frac{\Delta_1}{\Delta_2}=2\)

\(\therefore \quad \Delta_1=2 \Delta_2\) or \(\frac{\Delta_1}{\Delta_2}=2\)
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