JEE Advanced · Mathematics · 25. AOD
Let \(f, g\) and \(h\) be real-valued functions defined on the interval \([0,1]\) by \(f(x)=e^{x^2}+e^{-x^2}, \quad g(x)=x e^{x^2}+e^{-x^2}\) and \(h(x)=x^2 e^{x^2}+e^{-x^2}\). If \(a, b\) and \(c\) denote respectively, the absolute maximum of \(f, g\) and \(h\) on \([0,1]\), then
- A
\(a=b\) and \(c \neq b\)
- B
\(a=c\) and \(a \neq b\)
- C
\(a \neq b\) and \(c \neq b\)
- D
\(a=b=c\)
Answer & Solution
Correct Answer
(D)
\(a=b=c\)
Step-by-step Solution
Detailed explanation
Given function,
\[
\begin{aligned}
& f(x)=e^{x^2}+e^{-x^2}, \\
& g(x)=x e^{x^2}+e^{-x^2} \text { and } \\
& h(x)=x^2 e^{x^2}+e^{-x^2} \text { are } \quad \text { strictly }
\end{aligned}
\]
increasing on \([0,1]\). Hence, at \(x=1\), the given function attains absolute maximum all equal to \(e+\frac{1}{e}\).
\[
\Rightarrow \quad a=b=c
\]
\[
\begin{aligned}
& f(x)=e^{x^2}+e^{-x^2}, \\
& g(x)=x e^{x^2}+e^{-x^2} \text { and } \\
& h(x)=x^2 e^{x^2}+e^{-x^2} \text { are } \quad \text { strictly }
\end{aligned}
\]
increasing on \([0,1]\). Hence, at \(x=1\), the given function attains absolute maximum all equal to \(e+\frac{1}{e}\).
\[
\Rightarrow \quad a=b=c
\]
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