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JEE Advanced · Mathematics · 29. Differential Eqns

Let f : 121R (the set of all real numbers) be a positive, non-constant and differentiable function such that f'x<2fx and f12=1. Then the value of 1 / 2 1 f x dx  lies in the interval:

  1. A 2 e - 1 2 e
  2. B e - 1 2 e - 1
  3. C e - 1 2 e - 1
  4. D 0 , e - 1 2
Verified Solution

Answer & Solution

Correct Answer

(D) 0 , e - 1 2

Step-by-step Solution

Detailed explanation

f'x<2fx
f'xfx<2 12xf'xfxdx=12x2dx
From JEE Advanced
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