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JEE Advanced · Mathematics · 22. Functions

Let f :-π2,π2R be given by fx=logsecx+tanx3. Then

  1. A fx is an odd function
  2. B fx is a one - one function
  3. C fx is an onto function
  4. D fx is an even function
Verified Solution

Answer & Solution

Correct Answer

(A) fx is an odd function

Step-by-step Solution

Detailed explanation

fx=logsecx+tanx3  x -π2,π2
f-x= -fx, hence fx is odd function
Let gx=secx+tanx  x -π2,π2
gx=secxsecx+tanx>0  x -π2,π2
gx is one - one function
Hence logegx3 is one - one function.
And gx 0,   x-π2,π2
loggx R Hence fx is an onto function.
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