JEE Advanced · Mathematics · 23. C&D
If \(f(x)=\min \left\{1, x^2, x^3\right\}\), then
- A
\(f(x)\) is continuous everywhere
- B
\(f(x)\) is continuous and differentiable everywhere
- C
\(f(x)\) is not differentiable at two points
- D
\(f(x)\) is not differentiable at one point
Answer & Solution
Correct Answer
(D)
\(f(x)\) is not differentiable at one point
Step-by-step Solution
Detailed explanation
Here, \(f(x)=\min .\left\{1, x^2, x^3\right\}\) which could be graphically shown as
\[
\therefore \quad f(x)=\left\{\begin{array}{c}
1, x \geq 1 \\
x^3, x < 1
\end{array}\right.
\]
\[
\Rightarrow f(x) \text { is continuous for } x \in R \text { and not differentiable at } x=1 \text { due to sharp edge. }
\]
\[
\therefore \quad f(x)=\left\{\begin{array}{c}
1, x \geq 1 \\
x^3, x < 1
\end{array}\right.
\]

\[
\Rightarrow f(x) \text { is continuous for } x \in R \text { and not differentiable at } x=1 \text { due to sharp edge. }
\]
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