JEE Advanced · Chemistry · 28. Amines
The smallest ketone and its next homologoue are reacted with \(\mathrm{NH}_2 \mathrm{OH}\) to form oxime
- A two different oximes are formed
- B three different oximes are formed
- C two oximes are optically active
- D all oximes are optically active
Answer & Solution
Correct Answer
(B) three different oximes are formed
Step-by-step Solution
Detailed explanation
Lowest ketone is \(\mathrm{CH}_3 \mathrm{COCH}_3\) (which form an oxime) and its next homologue is \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COCH}_3\) which form oxime with \(\mathrm{NH}_2 \mathrm{OH}\). Such oxime shows the property of geometrical isomerism, i.e., it shows two isomers, symmetric and antisymmertic. (These are differ w.r.t. arrangement towards the space of \(-\mathrm{C}=\mathrm{N}\), their different behaviour, can be confirmed with the help of Beckmann's rearrangement.




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