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JEE Advanced · Chemistry · 18. Chemical Kinetics

In the decay sequence:
U92238-x1Th90234-x2Pa91234-x3Z 234-x4Th90234
x1, x2, x3 and x4 are the particles/ radiation emitted by the respective isotopes. The correct option(s) is/are:

  1. A Z is an isotope of uranium.
  2. B x2 is β-.
  3. C x1 will deflect towards the negatively charged plate.
  4. D x3 is γ-ray.
Verified Solution

Answer & Solution

Correct Answer

(A) Z is an isotope of uranium.

Step-by-step Solution

Detailed explanation

\({ }_{92}\text U \xrightarrow{-\frac{4}{2} \propto}{ }_{90}^{23} \text{Th} \xrightarrow{^{-0}_{-1} \beta}{ }_{91}^{234} \text{Pa} \xrightarrow{^{-0}_{-1} \beta}{ }_{92}^{234}\)\(\text U \xrightarrow{-\frac{4}{2} \propto}{ }_{90}^{234} \text{Th}\)
\(\text{I.e., }\text{x}_1=\alpha,\text x_2=\beta,\text x_3=\beta\) and \(\text x_4=\alpha\).
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