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GUJCET · Physics · Dual Nature of Radiation and Matter
The relation between the wavelength of electromagnetic radiation \((\lambda)\) and the de Broglie wavelength of its quantum (photon) \(\left(\lambda^{\prime}\right)\) is ___________.
- A \(\lambda^{\prime}>\lambda\)
- B \(\lambda^{\prime}=\lambda\)
- C \(\lambda^{\prime}<\lambda\)
- D \(\lambda^{\prime}=\frac{\lambda}{2}\)
Answer & Solution
Correct Answer
(B) \(\lambda^{\prime}=\lambda\)
Step-by-step Solution
Detailed explanation
\(\lambda^{\prime}=\lambda\)
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