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GUJCET · Physics · Electrostatic Potential and Capacitance
A parallel plate capacitor having air as dielectric medium is charged by a potential difference of V volt. After disconnecting the battery, the distance between the plates of the capacitor is increased using an insulated handle. As a result potential difference between the plates _________.
- A does not change.
- B decreases.
- C increases.
- D becomes zero.
Answer & Solution
Correct Answer
(C) increases.
Step-by-step Solution
Detailed explanation
(C)
When the battery is disconnected, the charge will remain same. Capacitance of a parallel plate capacitor is given by \(C =\frac{ A \varepsilon_0}{d}\) When the distance between two plate is increased, capacitance will decrease and the charge remains the same, so according to Q=CV, the voltage will increase.
When the battery is disconnected, the charge will remain same. Capacitance of a parallel plate capacitor is given by \(C =\frac{ A \varepsilon_0}{d}\) When the distance between two plate is increased, capacitance will decrease and the charge remains the same, so according to Q=CV, the voltage will increase.
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