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GUJCET · Physics · Nuclei
Calculate the height of the potential barrier for a head on collision of two deuterons. (Radius of deuteron is 2 fm).
- A \(7.2 \times 10^{-19} J\)
- B \(7.2 \times 10^{-14} J\)
- C \(3.6 \times 10^{-19} J\)
- D \(5.76 \times 10^{-14} J\)
Answer & Solution
Correct Answer
(D) \(5.76 \times 10^{-14} J\)
Step-by-step Solution
Detailed explanation
\(V = \frac{k e^2}{r}\) \(V = \frac{(9 \times 10^9) (1.6 \times 10^{-19})^2}{2 \times (2 \times 10^{-15})}\)
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