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GUJCET · Maths · Continuity and Differentiability

\(\frac{d}{d x}\left(\operatorname{cosec}^{-1} e^x\right)=\) __________

  1. A \(\frac{1}{\sqrt{e^{2 x}-1}}\)
  2. B \(\sin ^{-1}\left(e^x\right)\)
  3. C \(\frac{-1}{\sqrt{e^{2 x}-1}}\)
  4. D \(\frac{-e^x}{\sqrt{e^{2 x}-1}}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{-1}{\sqrt{e^{2 x}-1}}\)

Step-by-step Solution

Detailed explanation

\(\frac{d}{d x}\left(\operatorname{cosec}^{-1} e^x\right) = \frac{-1}{|e^x|\sqrt{(e^x)^2-1}} \cdot e^x\) \(= \frac{-1}{e^x\sqrt{e^{2x}-1}} \cdot e^x\)