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GUJCET · Maths · Continuity and Differentiability
\(\frac{d}{d x}\left(\operatorname{cosec}^{-1} e^x\right)=\) __________
- A \(\frac{1}{\sqrt{e^{2 x}-1}}\)
- B \(\sin ^{-1}\left(e^x\right)\)
- C \(\frac{-1}{\sqrt{e^{2 x}-1}}\)
- D \(\frac{-e^x}{\sqrt{e^{2 x}-1}}\)
Answer & Solution
Correct Answer
(C) \(\frac{-1}{\sqrt{e^{2 x}-1}}\)
Step-by-step Solution
Detailed explanation
\(\frac{d}{d x}\left(\operatorname{cosec}^{-1} e^x\right) = \frac{-1}{|e^x|\sqrt{(e^x)^2-1}} \cdot e^x\) \(= \frac{-1}{e^x\sqrt{e^{2x}-1}} \cdot e^x\)
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