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GUJCET · Physics · Magnetism And Matter
At a place on Earth, the vertical component of Earth's magnetic field is \(\sqrt{3}\) times its horizontal component. The angle of dip at this place is ________.
- A \(30^{\circ}\)
- B \(60^{\circ}\)
- C \(45^{\circ}\)
- D \(0^{\circ}\)
Answer & Solution
Correct Answer
(B) \(60^{\circ}\)
Step-by-step Solution
Detailed explanation
B
\(\tan I =\frac{ Z _{ E }}{ H _{ E }}\)
\(\begin{array}{l}\therefore \quad \tan I =\frac{\sqrt{3} H _{ E }}{ H _{ E }} \\ \quad\left(\because Z _{ E }=\sqrt{3} H _{ E }\right)\end{array}\)
\(\begin{aligned} \therefore \quad \tan I =\sqrt{3} \\ =60^{\circ}\end{aligned}\)
\(\tan I =\frac{ Z _{ E }}{ H _{ E }}\)
\(\begin{array}{l}\therefore \quad \tan I =\frac{\sqrt{3} H _{ E }}{ H _{ E }} \\ \quad\left(\because Z _{ E }=\sqrt{3} H _{ E }\right)\end{array}\)
\(\begin{aligned} \therefore \quad \tan I =\sqrt{3} \\ =60^{\circ}\end{aligned}\)
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