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GUJCET · Physics · Electric Charges and Fields
An electrical dipole coincides on \(z\)-axis and its midpoint is on origin of the coordinate system. The electric field at an axial point at a distance \(z\) from origin is \(\overrightarrow{ E }(z)\) and electric field at an equatorial point at a distance \(y\) from origin is \(\overrightarrow{ E }(y)\).
Here \(z=y \gg a\)
so \(\left|\frac{\overrightarrow{ E }(z)}{\overrightarrow{ E }(y)}\right|=\) ________.
- A 1
- B 4
- C 3
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
(D)
Electric field at an axial point
\(\overrightarrow{ E }(z)=\frac{2 k p}{z^3} \quad \dot{p} \quad z \gg a\)
→ Electric field at an equitorial point
\(\overrightarrow{ E }(y)=-\frac{k p}{y^3} \quad \hat{p} \quad y \gg a\)
\(\therefore\left|\frac{\overrightarrow{ E }(z)}{\overrightarrow{ E }(y)}\right|=2\)
Electric field at an axial point
\(\overrightarrow{ E }(z)=\frac{2 k p}{z^3} \quad \dot{p} \quad z \gg a\)
→ Electric field at an equitorial point
\(\overrightarrow{ E }(y)=-\frac{k p}{y^3} \quad \hat{p} \quad y \gg a\)
\(\therefore\left|\frac{\overrightarrow{ E }(z)}{\overrightarrow{ E }(y)}\right|=2\)
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