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GUJCET · Maths · Differential Equations

The order and degree of differential equation \(\left\{1+\left(\frac{d y}{d x}\right)^2\right\}^{\frac{3}{2}}=\frac{d^2 y}{d x^2}\) are \(p\) and \(q\) respectively. then, \(p+q=\) ____________ .

  1. A 2
  2. B 6
  3. C 4
  4. D 5
Verified Solution

Answer & Solution

Correct Answer

(C) 4

Step-by-step Solution

Detailed explanation

\(\left\{1+\left(\frac{d y}{d x}\right)^2\right\}^3 = \left(\frac{d^2 y}{d x^2}\right)^2\) \(p = \text{Order} = 2\)