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GUJCET · Maths · Inverse Trigonometric Functions

\(\cos \left(\sin ^{-1} \frac{1}{5}+\cos ^{-1} x\right)=0 \text { then, } x=\) ____________ .

  1. A 0
  2. B \(\frac{1}{5}\)
  3. C 5
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{5}\)

Step-by-step Solution

Detailed explanation

\( \sin^{-1} \frac{1}{5} + \cos^{-1} x = \frac{\pi}{2} \) \( \cos^{-1} x = \frac{\pi}{2} - \sin^{-1} \frac{1}{5} \)