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GUJCET · Maths · Inverse Trigonometric Functions
\(\cos \left(\sin ^{-1} \frac{1}{5}+\cos ^{-1} x\right)=0 \text { then, } x=\) ____________ .
- A 0
- B \(\frac{1}{5}\)
- C 5
- D 1
Answer & Solution
Correct Answer
(B) \(\frac{1}{5}\)
Step-by-step Solution
Detailed explanation
\( \sin^{-1} \frac{1}{5} + \cos^{-1} x = \frac{\pi}{2} \) \( \cos^{-1} x = \frac{\pi}{2} - \sin^{-1} \frac{1}{5} \)
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