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GUJCET · Maths · Differential Equations

The integrating factor of differential equation \(\left(\tan ^{-1} y-x\right) d y=\left(1+y^2\right) d x\) is ____________ .

  1. A \(\tan ^{-1} y\)
  2. B \(\frac{1}{1+y^2}\)
  3. C \(e^{\frac{1}{1+y^{\prime}}}\)
  4. D \(e^{\tan ^{-1} y}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(e^{\tan ^{-1} y}\)

Step-by-step Solution

Detailed explanation

\( \frac{dx}{dy} = \frac{\tan^{-1} y - x}{1+y^2} \) \( \frac{dx}{dy} + \frac{1}{1+y^2}x = \frac{\tan^{-1} y}{1+y^2} \)