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GUJCET · Maths · Integrals
\(\int \sqrt{\frac{\cos x-\cos ^3 x}{1-\cos ^3 x}} d x=\) __________ \(+C\).
- A \(\frac{2}{3} \cos ^{-1}\left(\cos ^{\frac{3}{2}} x\right)\)
- B \(-\frac{2}{3} \cos ^{-1}\left(\cos ^{\frac{3}{2}} x\right)\)
- C \(\frac{3}{2} \cos ^{-1}\left(\cos ^{\frac{3}{2}} x\right)\)
- D \(-\frac{3}{2} \cos ^{-1}\left(\cos ^{\frac{3}{2}} x\right)\)
Answer & Solution
Correct Answer
(A) \(\frac{2}{3} \cos ^{-1}\left(\cos ^{\frac{3}{2}} x\right)\)
Step-by-step Solution
Detailed explanation
\(I = \int \sqrt{\frac{\cos x(1-\cos ^2 x)}{1-\cos ^3 x}} d x = \int \frac{\sin x \sqrt{\cos x}}{\sqrt{1-\cos ^3 x}} d x\) Let \(u = \cos^{\frac{3}{2}} x\). Then \(du = -\frac{3}{2} \cos^{\frac{1}{2}} x \sin x d x \implies \sin x \sqrt{\cos x} d x = -\frac{2}{3} d u\).
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