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GUJCET · Maths · Relations and Functions
Let \(f: {N} \rightarrow {N}\) be defined by \(f(n) = \begin{cases} \frac{n+1}{2} & ; \text{if } n \text{ is odd} \\ \frac{n}{2} & ; \text{if } n \text{ is even} \end{cases}\), for all \(n \in \mathbb{N}\) then \(f\) is ________.
- A One - one but not onto
- B One - one and onto
- C Many - one and onto
- D Neither one - one nor onto
Answer & Solution
Correct Answer
(C) Many - one and onto
Step-by-step Solution
Detailed explanation
\(f(1) = \frac{1+1}{2} = 1\) \(f(2) = \frac{2}{2} = 1\)
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