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GUJCET · Chemistry · Electrochemistry
Resistance of a conductivity cell filled with 0.1 M KCl solution is \(100 \Omega\) and conductivity of solution is \(1.29 S / m\). Then what will be the value of conductivity of cell constant ?
- A \(1.29 cm^{-1}\)
- B \(1.29 m^{-1}\)
- C \(1.24 cm^{-1}\)
- D \(0.248 m^{-1}\)
Answer & Solution
Correct Answer
(A) \(1.29 cm^{-1}\)
Step-by-step Solution
Detailed explanation
A
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