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GUJCET · Maths · Inverse Trigonometric Functions
The number of real solutions of the equation \(\tan ^{-1} \sqrt{x(x+1)}+\sin ^{-1} \sqrt{x^2+x+1}=\frac{\pi}{2}\) is ___________ .
- A 1
- B 3
- C 2
- D 4
Answer & Solution
Correct Answer
(C) 2
Step-by-step Solution
Detailed explanation
\( \tan^{-1} \sqrt{x(x+1)} \): \( x(x+1) \ge 0 \implies x \in (-\infty, -1] \cup [0, \infty) \) \( \sin^{-1} \sqrt{x^2+x+1} \): \( 0 \le \sqrt{x^2+x+1} \le 1 \)
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