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GUJCET · Maths · Vector Algebra
For any three vecter \(\vec{a}, \vec{b}\) and \(\vec{c}\), If \(\vec{a}+\vec{b}+\vec{c}=\overrightarrow{0}\) and \(|\vec{a}|=3,|\vec{b}|=4,|\vec{c}|=2\) then, \(\vec{a} \cdot \vec{b}+\vec{b} \cdot \vec{c}+\vec{c} \cdot \vec{a}=\) _________ .
- A \(-\frac{9}{2}\)
- B 29
- C \(\frac{29}{2}\)
- D \(-\frac{29}{2}\)
Answer & Solution
Correct Answer
(D) \(-\frac{29}{2}\)
Step-by-step Solution
Detailed explanation
\(|\vec{a}+\vec{b}+\vec{c}|^2 = |\vec{a}|^2 + |\vec{b}|^2 + |\vec{c}|^2 + 2(\vec{a} \cdot \vec{b} + \vec{b} \cdot \vec{c} + \vec{c} \cdot \vec{a})\) \( {0} ^2 = 3^2 + 4^2 + 2^2 + 2(\vec{a} \cdot \vec{b} + \vec{b} \cdot \vec{c} + \vec{c} \cdot \vec{a})\)
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