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GUJCET · Maths · Continuity and Differentiability
If \(f(x)=\left\{\begin{array}{cl}\frac{x^3+x^2-16 x+20}{(x-2)^2} & , x \neq 2 \\ k & , x=2\end{array}\right.\) is continuous at \(x=2\) then \(k=\) ___________ .
- A -7
- B 7
- C -5
- D 5
Answer & Solution
Correct Answer
(B) 7
Step-by-step Solution
Detailed explanation
For continuity, \( \lim_{x \to 2} f(x) = f(2) \) \( \lim_{x \to 2} \frac{x^3+x^2-16 x+20}{(x-2)^2} = k \)
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