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GUJCET · Maths · Probability
A man is known to speak truth 4 out of 5 times. He throws a die and reports that it is a six. The probability that actually there was a six is
- A \(\frac{5}{9}\)
- B \(\frac{4}{9}\)
- C \(\frac{5}{35}\)
- D \(\frac{4}{35}\)
Answer & Solution
Correct Answer
(B) \(\frac{4}{9}\)
Step-by-step Solution
Detailed explanation
\(P(\text{Actual six}) = \frac{1}{6}\) \(P(\text{No actual six}) = \frac{5}{6}\)
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