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GUJCET · BIOLOGY · Molecular Basis of Inheritance

Choose the correct option for conclusion of Hershey Chase experiment.

  1. A Experiment - Bacteriophage, Radioactive \(\left({ }^{32} S\right)\) labelled protein capsule
    Conclusion - Radioactive \(\left({ }^{32} S\right)\)detected in cells\(+\)No Radioactivitydetected in supernatant
  2. B Experiment - Radioactive \(\left({ }^{32} P \right)\) labelled DNA
    Conclusion - No Radioactive detected in cells \(+\) Radioactive detected ( \({ }^{32} P\) ) in supernatant
  3. C Experiment - Bacteriophage Radioactive \(\left({ }^{35} S\right)\)
    Conclusion - No Radioactive\(\left({ }^{32} S\right)\) detected inlabelled proteincellsCapsule\(+\)Radioactive \(\left({ }^{35} S\right)\)detected in supernatant
  4. D Experiment - Radioactive \(\left({ }^{32} P \right)\) labelled DNA
    Conclusion - Radioactive \(\left({ }^{35} P \right)\)detected in cells\(+\)No Radioactivity detected in supernatant
Verified Solution

Answer & Solution

Correct Answer

(C) Experiment - Bacteriophage Radioactive \(\left({ }^{35} S\right)\)
Conclusion - No Radioactive\(\left({ }^{32} S\right)\) detected inlabelled proteincellsCapsule\(+\)Radioactive \(\left({ }^{35} S\right)\)detected in supernatant

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Detailed explanation

C