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GUJCET · Maths · Inverse Trigonometric Functions
The value of \(\tan ^{-1}(-1)+\sec ^{-1}(-2)+\sin ^{-1} \frac{1}{\sqrt{2}}\) is ____________ .
- A \(-\frac{\pi}{3}\)
- B \(-\frac{\pi}{6}\)
- C \(\pi\)
- D \(\frac{2 \pi}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{2 \pi}{3}\)
Step-by-step Solution
Detailed explanation
\(\tan ^{-1}(-1)=-\frac{\pi}{4}\) \(\sec ^{-1}(-2)=\frac{2\pi}{3}\)
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