AP EAMCET · PHYSICS · Electromagnetic Induction
When current in a coil changes from 2 A to 5 A in a time of 0.3 s, if the emf induced in the coil is 40 mV, then the self inductance of the coil is
- A 4 H
- B 4 mH
- C 40 mH
- D \(4 \mu \mathrm{H}\)
Answer & Solution
Correct Answer
(B) 4 mH
Step-by-step Solution
Detailed explanation
\( \varepsilon = L \frac{\Delta I}{\Delta t} \) \( 40 \times 10^{-3} \, \mathrm{V} = L \frac{(5 \, \mathrm{A} - 2 \, \mathrm{A})}{0.3 \, \mathrm{s}} \) \( 40 \times 10^{-3} = L \frac{3}{0.3} \) \( L = \frac{40 \times 10^{-3}}{10} \, \mathrm{H} \)…
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