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AP EAMCET · PHYSICS · Waves and Sound

When a stretched wire of fundamental frequency \(f\) is divided into three segments, the fundamental frequencies of these three segments are \(f_1, f_2\) and \(f_3\) respectively. Then the relation among \(\mathrm{f}_1, \mathrm{f}_2, \mathrm{f}_3\) and f is (Assume tension is constant)

  1. A \(\sqrt{\mathrm{f}}=\sqrt{\mathrm{f}_1}+\sqrt{\mathrm{f}_2}+\sqrt{\mathrm{f}_3}\)
  2. B \(\mathrm{f}=\mathrm{f}_1+\mathrm{f}_2+\mathrm{f}_3\)
  3. C \(\frac{1}{\mathrm{f}}=\frac{1}{\mathrm{f}_1}+\frac{1}{\mathrm{f}_2}+\frac{1}{\mathrm{f}_3}\)
  4. D \(\frac{1}{\sqrt{\mathrm{f}}}=\frac{1}{\sqrt{\mathrm{f}_1}}+\frac{1}{\sqrt{\mathrm{f}_2}}+\frac{1}{\sqrt{\mathrm{f}_3}}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{\mathrm{f}}=\frac{1}{\mathrm{f}_1}+\frac{1}{\mathrm{f}_2}+\frac{1}{\mathrm{f}_3}\)

Step-by-step Solution

Detailed explanation

\(L \propto \frac{1}{f}\) (since \(f = \frac{1}{2L}\sqrt{\frac{T}{\mu}}\) and \(T, \mu\) are constant) \(L = L_1 + L_2 + L_3\) \(\frac{1}{f} = \frac{1}{f_1} + \frac{1}{f_2} + \frac{1}{f_3}\)
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