AP EAMCET · PHYSICS · Magnetic Effects of Current
An alpha particle moves along a circular path of radius 0.5 mm in a magnetic field of \(2 \times 10^{-2} \mathrm{~T}\). The de Broglie wavelength associated with the alpha particle is nearly
\(\left(\right.\) Planck's constant \(\left.=6.63 \times 10^{-34} \mathrm{~J} \mathrm{~s}\right)\)
- A \(3.1 Å\)
- B \(1.1 Å\)
- C \(0.1 Å\)
- D \(2.1 Å\)
Answer & Solution
Correct Answer
(D) \(2.1 Å\)
Step-by-step Solution
Detailed explanation
\(p = qBr\) \(\lambda = \frac{h}{p} = \frac{h}{qBr}\) \(\lambda = \frac{6.63 \times 10^{-34}}{(2 \times 1.602 \times 10^{-19}) \times (2 \times 10^{-2}) \times (0.5 \times 10^{-3})}\) \(\lambda \approx 2.069 \times 10^{-10} \mathrm{~m}\) \(\lambda \approx 2.1 \text{ Å}\)
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