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AP EAMCET · PHYSICS · Motion In Two Dimensions

Two towers A and B, each of height 20 m are situated a distance 200 m apart. A body thrown horizontally from the top of the tower A with a velocity 20 ms-1 towards the tower B hits the ground at point P and another body thrown horizontally from the top of tower B with a velocity 30 ms-1 towards the tower A hits the ground at point Q. If a car starting from rest from P reaches Q in 10 seconds, the acceleration of the car is _________ (Acceleration due to gravity =10 ms-2)

  1. A 1 ms-2
  2. B 2 ms-2
  3. C 3 ms-2
  4. D 4 ms-2
Verified Solution

Answer & Solution

Correct Answer

(B) 2 ms-2

Step-by-step Solution

Detailed explanation

The time taken by both the ball to reach the ground is same because initial vertical velocity and height of the tower is the same in each case,AP=20×2hg=20×4010=40 mQB=20×2hg=30×4010=60 mPQ=200-100=ut+12at2=0+12×a100100=50aa=2 m s-2