AP EAMCET · Maths · Circle
The equations of tangents to the circle \(x^2+y^2=10\) from the point \((4,-2)\) are
- A \(x+y=2,3 x+2 y=16\)
- B \(5 x+y=18,3 x-y=4\)
- C \(3 x+y=10, x-3 y=10\)
- D \(5 x-y=4, x+y=0\)
Answer & Solution
Correct Answer
(C) \(3 x+y=10, x-3 y=10\)
Step-by-step Solution
Detailed explanation
For a tangent, length of perpendicular from origin \(=\) radius. So we check distance from \((0,0)\) and for any tangent it must be \(\sqrt{10}\). For \(3 x+y=10\) and \(x-3 y=10\), Distance of \((0,0)\) from line \(3 x+y=10\) is,…
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