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AP EAMCET · PHYSICS · Waves and Sound

Two sources \(A\) and \(B\) are producing notes of frequency \(680 \mathrm{~Hz}\). A listener moves from \(A\) to \(B\) with a constant velocity \(v\). if the speed of sound in air is \(340 \mathrm{~ms}^{-1}\), the value of \(y\) so that he hears 10 beats per second is

  1. A \(2.0 \mathrm{~ms}^{-1}\)
  2. B \(2.5 \mathrm{~ms}^{-1}\)
  3. C \(3.0 \mathrm{~ms}^{-1}\)
  4. D \(3.5 \mathrm{~ms}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2.5 \mathrm{~ms}^{-1}\)

Step-by-step Solution

Detailed explanation

Given, notes of frequency produced by the sources \(A\) and \(B\) is \(680 \mathrm{~Hz}\). i. e., \(f_A\) and \(f_B=680 \mathrm{~Hz}\) Velocity of listener moves from \(A\) to \(B\) is constant \(=v\), speed of sound, \(v_s=340 \mathrm{~m} / \mathrm{s}\), and beats per second,…