AP EAMCET · PHYSICS · Wave Optics
Two point sources \(S_1\) and \(S_2\) separated by a distance \(10 \mu \mathrm{m}\) emit light waves of wavelength \(4 \mu \mathrm{m}\) in phase. A circular wire of radius \(40 \mu \mathrm{m}\) is placed around the sources as shown in figure, then ( \(O\) is the centre of the circle and \(O S_1=O S_2\) )

- A points \(A\) and \(B\) are dark and points \(C\) and \(D\) are bright
- B points \(A\) and \(B\) are bright and point \(C\) and \(D\) are dark
- C points \(A\) and \(C\) are dark and points \(B\) and \(D\) are bright
- D points \(A\) and \(C\) are bright and points \(B\) and \(D\) are dark
Answer & Solution
Correct Answer
(C) points \(A\) and \(C\) are dark and points \(B\) and \(D\) are bright
Step-by-step Solution
Detailed explanation
Path difference at point \(B\), \[ \Delta x_B=S_1 B-S_2 B=0 \] and at point \(D\), \[ \Delta x_D=S_1 D-S_2 D=0 \] Phase difference, \[ \phi=\frac{2 \pi}{\lambda} \times(0)=0 \] So, intensity at points \(B\) and \(D\) \[ I=I_{\max } \cos ^2(\phi / 2)=I_{\max } \] So, points \(B\)…
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